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11x+15=2x^2
We move all terms to the left:
11x+15-(2x^2)=0
determiningTheFunctionDomain -2x^2+11x+15=0
a = -2; b = 11; c = +15;
Δ = b2-4ac
Δ = 112-4·(-2)·15
Δ = 241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{241}}{2*-2}=\frac{-11-\sqrt{241}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{241}}{2*-2}=\frac{-11+\sqrt{241}}{-4} $
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